[LeetCode] Self Dividing Numbers 自整除數字

阿新 • • 發佈：2017-11-28

bounds 整除 leetcode dig ins dividing num per ssi

A self-dividing number is a number that is divisible by every digit it contains.

For example, 128 is a self-dividing number because 128 % 1 == 0, 128 % 2 == 0, and 128 % 8 == 0.

Also, a self-dividing number is not allowed to contain the digit zero.

Given a lower and upper number bound, output a list of every possible self dividing number, including the bounds if possible.

Example 1:

Input: 
left = 1, right = 22
Output: [1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]

Note:

The boundaries of each input argument are 1 <= left <= right <= 10000.

[LeetCode] Self Dividing Numbers 自整除數字

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自除數是指可以被它包含的每一位數除盡的數。例如，128 是一個自除數，因為 128 % 1 == 0，128 % 2 == 0，128 % 8 == 0。還有，自除數不允許包含 0 。給定上邊界和下邊界數字，輸出一個列表，列表的元素是邊界（含邊界）內所有的自除數

Self Dividing Numbers 自除數

自除數是指可以被它包含的每一位數除盡的數。例如，128 是一個自除數，因為 128 % 1 == 0，128 % 2 == 0，128 % 8 == 0。還有，自除數不允許包含 0 。給定上邊界和下邊界數字，輸出一個列表，列表的元素是邊界（含邊界）內所有的自除

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[LeetCode] Self Dividing Numbers 自整除數字

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