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Reservoir Sampling-382. Linked List Random Node

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Given a singly linked list, return a random node‘s value from the linked list. Each node must have the same probability of being chosen.

Follow up:
What if the linked list is extremely large and its length is unknown to you? Could you solve this efficiently without using extra space?

Example:

// Init a singly linked list [1,2,3].
ListNode head = new ListNode(1);
head.next = new ListNode(2);
head.next.next = new ListNode(3);
Solution solution = new Solution(head);

// getRandom() should return either 1, 2, or 3 randomly. Each element should have equal probability of returning.
solution.getRandom();

class Solution {
public:
    /** @param head The linked list‘s head.
        Note that the head is guaranteed to be not null, so it contains at least one node. */
    Solution(ListNode* head):cur(head) {
    }

    /** Returns a random node‘s value. */
    int getRandom() {
        int val=cur->val;
        ListNode 
*temp=cur; for(int i=0;temp!=nullptr;temp=temp->next,++i) { uniform_int_distribution<unsigned> u(0,i); default_random_engine e(rand());//真正隨機的種子 unsigned int m=u(e); if(m<1) { val=temp->val; } }
return val; } private: ListNode *cur; };

Reservoir Sampling-382. Linked List Random Node