[leetcode]633. Sum of Square Numbers
雙指針比較簡單的應用,搜索範圍要註意
public boolean judgeSquareSum(int c) { /* 雙指針,搜索範圍是0到sqrt(c) */ if (c<0) return false; int left = 0; int right = (int)Math.sqrt(c); while (left<=right) { int cur = left*left+right*right; if (c>cur) left++;else if (c<cur) right--; else return true; } return false; }
[leetcode]633. Sum of Square Numbers
相關推薦
[leetcode]633. Sum of Square Numbers
body ges sum pre -- mat sqrt else 註意 雙指針比較簡單的應用,搜索範圍要註意 public boolean judgeSquareSum(int c) { /* 雙指針,搜索範圍是0到sqrt(c)
leetcode:(633) Sum Of Square Numbers(java)
題目: Given a non-negative integer c, your task is to decide whether there're two integers a and b 
[LeetCode] 633. Sum of Square Numbers
題目 Given a non-negative integer c, your task is to decide whether there’re two integers a and b such that a2 + b2 = c. Example 1:
Leetcode——633. Sum of Square Numbers
題目原址 題目描述 Given a non-negative integer c, your task is to decide whether there’re two integers
633. Sum of Square Numbers(平方和)(leetcode)
時間復雜度 ron html lis src hide 平方根 you HERE 題目: Given a non-negative integer c, your task is to decide whether there‘re two integers a and b
633. Sum of Square Numbers
pla numbers task -- boolean color else integer while Given a non-negative integer c, your task is to decide whether there‘re two integers
【LeetCode】633. 平方數之和(Sum of Square Numbers)
【 英文練習 | 中文練習 】 題目描述: 給定一個非負整數 c ,你要判斷是否存在兩個整數 a 和 b,c 等於 a 和 b 的平方和。 示例: 輸入: 5 輸出: True 解釋: 1 * 1 + 2 * 2 = 5 解法一: 利用雙指標的思想,需要注意兩個坑點,一
C#LeetCode刷題之#633-平方數之和( Sum of Square Numbers)
問題 給定一個非負整數 c ,你要判斷是否存在兩個整數 a 和 b,使得 a2 + b2 = c。 輸入: 5 輸出: True 解釋: 1 * 1 + 2 * 2 = 5 輸入: 3
leetcode 633. 平方數之和(Sum of Square Numbers)
-- etc 題目 while code ++ title int div 目錄 題目描述: 示例1: 示例2: 解法: 題目描述: 給定一個
[LeetCode] Sum of Square Numbers 平方數之和
Given a non-negative integer c, your task is to decide whether there're two integers a and b such that a2 + b2 = c. Example 1: Input: 5 Output: True
lintcode: Check Sum of Square Numbers
floor data- logs footer -s div strong you cksum Check Sum of Square Numbers Given a integer c, your task is to decide whether there‘
Sum of Square Numbers 平方數之和
給定一個非負整數 c ,你要判斷是否存在兩個整數 a 和 b,使得 a2 + b2 = c。 示例1: 輸入: 5 輸出: True 解釋: 1 * 1 + 2 * 2 = 5 示例2: 輸入: 3 輸出: False 思路:因為要滿足a^2+b^2=c,所以a的
Sum of Square Numbers
Given a non-negative integer c, your task is to decide whether there're two integers a and b such that a2 + b2 =
LeetCode 985 Sum of Even Numbers After Queries 解題報告
self mon 一個 val span class for return pan 題目要求 We have an array A of integers, and an array queries of queries. For the i-th query val =
#Leetcode# 985. Sum of Even Numbers After Queries
should mono eve base -a out spa tco after https://leetcode.com/problems/sum-of-even-numbers-after-queries/ We have an array A of inte
【leetcode】985. Sum of Even Numbers After Queries
leetcode 執行 pre code self urn type sel gin 題目如下: We have an array A of integers, and an array queries of queries. For the i-th query val
Leetcode-5017 Sum of Root To Leaf Binary Numbers(從根到葉的二進制數之和)
void leaf int ret number ber numbers num bin 1 typedef long long ll; 2 class Solution 3 { 4 public: 5 ll rnt = 0;
[leetcode-404-Sum of Left Leaves]
葉子 fin esp binary cnblogs values tree roo col Find the sum of all left leaves in a given binary tree. Example: 3 / 9 20 /
[LeetCode] Maximum Product of Three Numbers
clas style find leet 數組元素 cat 兩個 bit bsp Given an integer array, find three numbers whose product is maximum and output the maximum produ
LeetCode: 371 Sum of Two Integers(easy)
pan per ret sum integer 計算 code 移位 etc 題目: Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -