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nyoj 991 Registration system (map)

one names aca prototype num ould all 成功 main

Registration system

時間限制:1000 ms | 內存限制:65535 KB 難度:2
描述

  A new e-mail service "Berlandesk" is going to be opened in Berland in the near future.

The site administration wants to launch their project as soon as possible, that‘s why they

ask you to help. You‘re suggested to implement the prototype of site registration system.

The system should work on the following principle.

Each time a new user wants to register, he sends to the system a request with his name.

If such a name does not exist in the system database, it is inserted into the database, and

the user gets the response OK, confirming the successful registration. If the name already

exists in the system database, the system makes up a new user name, sends it to the user

as a prompt and also inserts the prompt into the database. The new name is formed by the

following rule. Numbers, starting with 1, are appended one after another to name (name1,

name2, ...), among these numbers the least i is found so that namei does not yet exist in

the database.

技術分享圖片

輸入
  The first line contains number n (1?≤?n?≤?105). The following n lines contain the requests to the system. Each request is a non-empty line, and consists of not more than 1000 characters, which are all lowercase Latin letters.
輸出
Print n lines, which are system responses to the requests: OK in case of successful registration, or a prompt with a new name, if the requested name is already taken.
樣例輸入
  4
  abacaba
  acaba
  abacaba
  acab
樣例輸出
  OK
  OK
  abacaba1
  OK
/**
    分析:該題是,判斷一個新輸入字符串是否屬於原先字符串序列
          ①"不屬於" : 打印"OK"表示插入成功
          ②"屬於"  : 判斷是第幾次出現該串(序列號)  -->  並打印:"該串" + 序列號 
    方法:map <string, int>
    模板:
        map <string, int> my_map;
        pair <map <string, int> :: iterator, bool> pr;
        
        pr = my_map.insert (map <string, int> (str, 0));
        if (!pr.second)  
        {
            ++ my_map [str];
            cout <<str <<my_map [str] <<endl; 
        } 
        else
        {
            cout <<"OK" <<endl;
        }
**/

C/C++代碼實現:

#include <iostream>
#include <algorithm>
#include <cstring>
#include <cmath>
#include <cstdio>
#include <stack>
#include <queue>
#include <map>

using namespace std;

int N;

string str;

int main () {
    ~scanf ("%d", &N);
    map <string, int> my_map;
    pair <map <string, int> :: iterator, bool> pr;
    
    while (N --) {
        cin >>str;
        pr = my_map.insert (pair <string, int> (str, 0));
        if (!pr.second) { // 插入失敗 
            my_map [str] ++;
            cout <<str <<my_map [str] <<endl;
        } else {
            printf ("OK\n");
        }
    }
    return 0;
}

nyoj 991 Registration system (map)