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JAVA大數貪心

args port 簡單 compare 一位 class big 題意 AI

題意:
01給出一個數n,現在要將它分為m個數,這m個數相加起來必須等於n,並且要使得這m個數的或值最小。

思路分析:

一個簡單的貪心,從高位到低位,判斷當前位可否為 1 ,若可以,則將所有的數的這一位全部都變成 1

代碼示例:

import java.math.*;
import java.util.*;

public class study {

	public static void main(String[] args) {	
		Scanner cin = new Scanner(System.in);
		BigInteger n, m;
		
		
		int t = cin.nextInt();
		for(int cas = 0; cas < t; cas++) {
			n = cin.nextBigInteger();
			m = cin.nextBigInteger();
			BigInteger ans = BigInteger.valueOf(0);
			
			int len = 0;
                        BigInteger ss = n, v = BigInteger.valueOf(0);
                        while(ss.compareTo(v)>0){
                            ss = ss.divide(BigInteger.valueOf(2));
                            len++;
                        }    
			
			for(int i = len; i >= 0; i--) {
				BigInteger tem = BigInteger.valueOf(2);
				tem = tem.pow(i).subtract(BigInteger.valueOf(1)).multiply(m);
				//System.out.println(tem);
				if (tem.compareTo(n) < 0) {
					BigInteger f = BigInteger.valueOf(2).pow(i);
					ans = ans.add(f);
					BigInteger p = n.divide(f);
					if (p.compareTo(m) >= 0) n = n.subtract(m.multiply(f));
					else n = n.subtract(p.multiply(f));
					//System.out.println(f);
					//System.out.println(p);
				}
			}
			System.out.println(ans);
		}
	}

}
           

JAVA大數貪心