1. 程式人生 > >ACboy needs your help(分組背包)

ACboy needs your help(分組背包)

lan line namespace tar pos indicate num return his

ACboy has N courses this term, and he plans to spend at most M days on study.Of course,the profit he will gain from different course depending on the days he spend on it.How to arrange the M days for the N courses to maximize the profit?

Input

The input consists of multiple data sets. A data set starts with a line containing two positive integers N and M, N is the number of courses, M is the days ACboy has.
Next follow a matrix A[i][j], (1<=i<=N<=100,1<=j<=M<=100).A[i][j] indicates if ACboy spend j days on ith course he will get profit of value A[i][j].
N = 0 and M = 0 ends the input.
Output

For each data set, your program should output a line which contains the number of the max profit ACboy will gain.
Sample Input

2 2
1 2
1 3
2 2
2 1
2 1
2 3
3 2 1
3 2 1
0 0

Sample Output

3
4
6
題目大意:
先輸入n,m代表n個課程和有m天,在輸入n*m的矩陣,分別代表經歷j天在i課程上,得到的一個權值,求大的權值。
#include <iostream>
#include <cstring>
using
namespace std; int a[105][105],dp[105]; int n,m; int main() { while(cin>>n>>m,n||m) { memset(dp,0,sizeof dp); for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) cin>>a[i][j]; for(int i=1;i<=n;i++) for(int j=m;j>=1
;j--) for(int k=1;k<=j;k++)///枚舉在i課程的天數 dp[j]=max(dp[j],dp[j-k]+a[i][k]); cout<<dp[m]<<\n; } return 0; }

 

ACboy needs your help(分組背包)