POJ 3126(BFS)
阿新 • • 發佈:2018-07-15
code stream using \n == bfs push string ostream
1 #include <iostream> 2 #include <cstdio> 3 #include <cmath> 4 #include <cstring> 5 #include <algorithm> 6 #include <queue> 7 using namespace std; 8 struct node 9 { 10 int x, step; 11 }s,e; 12 int n, m,vis[10010]; 13 int shushu(int k) 14 { 15 int t = sqrt(k);16 for (int i = 2; i <= t; i++) 17 { 18 if (k%i == 0) 19 return 0; 20 } 21 return 1; 22 } 23 void bfs() 24 { 25 node temp, next; 26 queue<node>q; 27 q.push(s); 28 while (!q.empty()) 29 { 30 temp = q.front(); q.pop(); 31 if (temp.x == m)32 { 33 printf("%d", temp.step); 34 return; 35 } 36 for (int i = 1; i < 10; i = i + 2)//枚舉個位 37 { 38 next.x = (temp.x / 10) * 10 + i; 39 if (next.x != temp.x&&vis[next.x] == 0 && shushu(next.x)) 40 {41 vis[next.x] = 1; 42 next.step = temp.step + 1; 43 q.push(next); 44 } 45 } 46 for (int i = 0; i < 10; i++)//枚舉十位 47 { 48 next.x = (temp.x / 100) * 100 + i * 10 + temp.x % 10; 49 if (next.x != temp.x&&vis[next.x] == 0 && shushu(next.x)) 50 { 51 vis[next.x] = 1; 52 next.step = temp.step + 1; 53 q.push(next); 54 } 55 } 56 for (int i = 0; i < 10; i++)//枚舉百位 57 { 58 next.x = (temp.x / 1000) * 1000 + i * 100+ temp.x % 100; 59 if (next.x != temp.x&&vis[next.x] == 0 && shushu(next.x)) 60 { 61 vis[next.x] = 1; 62 next.step = temp.step + 1; 63 q.push(next); 64 } 65 } 66 for (int i = 1; i < 10; i++)//枚舉千位 67 { 68 next.x = i*1000 + temp.x % 1000; 69 if (next.x != temp.x&&vis[next.x] == 0 && shushu(next.x)) 70 { 71 vis[next.x] = 1; 72 next.step = temp.step + 1; 73 q.push(next); 74 } 75 } 76 } 77 } 78 int main() 79 { 80 int t; 81 scanf("%d",&t); 82 while (t--) 83 { 84 scanf("%d%d",&n,&m); 85 s.x = n; 86 memset(vis, 0, sizeof(vis)); 87 vis[n] = 1; 88 s.step = 0; 89 bfs(); 90 printf("\n"); 91 } 92 return 0; 93 }
POJ 3126(BFS)