Find the Duplicate Number--循環鏈表
阿新 • • 發佈:2018-07-20
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Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one.
Example 1:
Input: [1,3,4,2,2]
Output: 2
Example 2:
Input: [3,1,3,4,2] Output:3
Note:
- You must not modify the array (assume the array is read only).
- You must use only constant, O(1) extra space.
- Your runtime complexity should be less than O(n2).
- There is only one duplicate number in the array, but it could be repeated more than once.
class Solution { public int findDuplicate(int[] nums) { int slow = 0, fast = 0; do { slow = nums[slow]; fast = nums[nums[fast]]; } while (nums[slow] != nums[fast]); slow = 0; while (nums[slow] != nums[fast]) { slow = nums[slow]; fast = nums[fast]; }return nums[slow]; } }
Find the Duplicate Number--循環鏈表