[算法]Python實現
阿新 • • 發佈:2018-09-15
== clas ++ class 全部 urn 多邊形 info odin
題目:
代碼:
# -*- coding:utf-8 -*- def rayCasting(p, poly): px = p[‘x‘] py = p[‘y‘] flag = False i = 0 l = len(poly) j = l - 1 #for(i = 0, l = poly.length, j = l - 1; i < l; j = i, i++): while i < l: sx = poly[i][‘x‘] sy = poly[i][‘y‘] tx = poly[j][‘x‘] ty = poly[j][‘y‘] #點與多邊形頂點重合 if (sx == px and sy == py) or (tx == px and ty == py): return (px, py) #判斷線段兩端點是否在射線兩側 if (sy < py and ty >= py) or (sy >= py and ty < py): #線段上與射線 Y 坐標相同的點的 X 坐標 x = sx + (py - sy) * (tx - sx) / (ty - sy) #點在多邊形的邊上 if x == px: return (px,py) #射線穿過多邊形的邊界 if x > px: flag = not flag j = i i += 1 #射線穿過多邊形邊界的次數為奇數時點在多邊形內 return (px,py) if flag else ‘out‘ #根據數組下標奇偶數得到點的坐標 def getpoint(a): i = 0 zhima = [] while i < len(a.split(‘,‘)[1::2]): zhima.append({‘x‘: float(a.split(‘,‘)[::2][i]),‘y‘: float(a.split(‘,‘)[1::2][i])}) i += 1 return zhima #根據輸入的點循環判斷芝麻是否在多邊形裏面,如果全部在外面則輸出no,否則輸出芝麻的坐標 def rs(zhima, duobianxing): zm = getpoint(zhima) dbx = getpoint(duobianxing) count = 0 for point in zm: rs = rayCasting(point, dbx) if rs == ‘out‘: count += 1 else: print rs if count == len(zm): print "no" zhima = "6,4,8,8,9,9" duobianxing = "1,1,7,3,5,7" rs(zhima,duobianxing)
結果:
[算法]Python實現