【HDUOJ】幾道遞推DP
阿新 • • 發佈:2018-10-11
題目 pac cout style http memset efi mem san
就不寫題解了。很基礎的遞推。
HDU2084數塔
題目鏈接:http://acm.hdu.edu.cn/showproblem.php?pid=2084
代碼:
1 #include <iostream> 2 #include <algorithm> 3 #include <cstdio> 4 #include <cstring> 5 6 using namespace std; 7 const int maxn = 105; 8 9 int dp[maxn][maxn]; 10 inta[maxn][maxn]; 11 12 int main(){ 13 int T; 14 cin>>T; 15 while(T--){ 16 memset(a,0,sizeof(a)); 17 memset(dp,0,sizeof(dp)); 18 int n; 19 cin>>n; 20 for(int i = 1; i <= n ;i++){ 21 for(int j = 1; j <= i; j++){22 cin>>a[i][j]; 23 } 24 } 25 26 for(int i = n; i > 0; i--){ 27 for(int j = 1; j <= n ;j++){ 28 dp[i][j] = max(dp[i+1][j] ,dp[i+1][j+1]) + a[i][j]; 29 } 30 } 31 cout<<dp[1][1]<<endl; 32 } 33 34 35 return 0; 36 }
HDU2018母牛的故事
題目鏈接:http://acm.hdu.edu.cn/showproblem.php?pid=2018
代碼:
1 #include <iostream> 2 #include <algorithm> 3 #include <cstdio> 4 #include <cstring> 5 6 using namespace std; 7 const int maxn = 105; 8 int dp[maxn]; 9 10 void init(){ 11 dp[1] = 1; 12 dp[2] = 2; 13 dp[3] = 3; 14 dp[4] = 4; 15 dp[5] = 6; 16 for(int i = 6; i <= 55; i++){ 17 dp[i] = dp[i-1] + dp[i-3]; 18 } 19 } 20 21 int main(){ 22 int n; 23 init(); 24 while(cin>>n && n){ 25 cout<<dp[n]<<endl; 26 } 27 28 return 0; 29 }
HDU2044小蜜蜂的故事
同類型HDU2041
題目鏈接:http://acm.hdu.edu.cn/showproblem.php?pid=2044
代碼:
1 #include <iostream> 2 #include <algorithm> 3 #include <cstdio> 4 #include <cstring> 5 #define ll long long 6 using namespace std; 7 const int maxn = 55; 8 ll fib[maxn]; 9 10 void init(){ 11 fib[0] = 0; 12 fib[1] = 1; 13 fib[2] = 2; 14 for(int i = 3 ;i <= maxn ;i++){ 15 fib[i] = fib[i-1] + fib[i-2]; 16 } 17 } 18 19 int main(){ 20 init(); 21 int n,m; 22 int T; 23 cin>>T; 24 while(T--){ 25 cin>>n>>m; 26 cout<<fib[m-n]<<endl; 27 } 28 29 30 return 0; 31 }
HDU2050
題目鏈接:http://acm.hdu.edu.cn/showproblem.php?pid=2050
代碼:
1 #include <iostream> 2 #include <algorithm> 3 #include <cstdio> 4 #include <cstring> 5 #define ll long long 6 using namespace std; 7 const int maxn = 10005; 8 ll dp[maxn]; 9 10 void init(){ 11 dp[1] = 2; 12 dp[2] = 7; 13 for(int i = 3; i <= maxn; i++){ 14 dp[i] = dp[i-1] + 4*(i-1) + 1; 15 } 16 } 17 18 int main(){ 19 int T; 20 cin>>T; 21 int n; 22 init(); 23 while(T--){ 24 cin>>n; 25 cout<<dp[n]<<endl; 26 } 27 28 return 0; 29 }
【HDUOJ】幾道遞推DP