1. 程式人生 > >The Josephus Problem

The Josephus Problem

The Josephus Problem 1000(ms) 65535(kb) 834 / 2034 The problem is named after Flavius Josephus, a Jewish historian whoparticipated in and chronicled the Jewish revolt of 66-70C.E.against the Romans. Josephus, as a general, managed to hold thefortress of Jotapata for 47days, but after the fall of the city hetook refuge with 40 diehards in a nearby cave. There the rebelsvoted to perish rather than surrender. Josephus proposed that eachman in turn should dispatch his neighbor, the order to bedetermined by casting lots. Josephus contrived to draw the lastlot, and as one of the two surviving men in the cave, he prevailedupon his intended victim to surrender to the Romans. Yourtask:computint the position of the survivor when there areinitially n people.

輸入

a Positive Integer n is initially  people. n< = 50000

輸出

the position of the survivor

樣例輸入

6

樣例輸出

5




@淺夏沫若.code:
#include
using namespace std; int main()
{
 int n = 0;
 int flag = 0;
 int counter = 0;
 int a[50001] = {0};
 cin >> n;
 while (1)
 {
  for (int i = 1; i <= n;i++)
  {
   if (flag ==1&&a[i]==0)
   {
    a[i]= 1;
    counter= counter + 1;
    flag= 0;
    if(counter == n - 1)
     break;
   }
   else if (flag== 0 && a[i] == 0)
   {
    flag= 1;
   }
  }
  if (counter == n - 1)
   break;
 }
 for(int i=1;i<=n;i++)
  if (a[i] == 0)
  {
   cout <<i << endl;
  }
 return 0;
}