[leetcode] #112 Path Sum (easy)
題意:
給定一個值,求出從樹頂到樹底(最後一個節點沒有子節點)有沒有一條路徑等於該值。
思路:
DFS
Runtime: 4 ms, faster than 100.00% of C++
class Solution { public: bool hasPathSum(TreeNode *root, int sum) { if (root == NULL) return false; if (root->val == sum && root->left==NULL && root->right==NULL)return true; return (root->left != NULL && hasPathSum(root->left, sum - root->val)) || (root->right != NULL && hasPathSum(root->right, sum - root->val)); } };
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