1002 寫出這個數 （20 分）

讀入一個正整數 n，計算其各位數字之和，用漢語拼音寫出和的每一位數字。

輸入格式：

每個測試輸入包含 1 個測試用例，即給出自然數 n 的值。這裡保證 n 小於 10​100​​。

輸出格式：

在一行內輸出 n 的各位數字之和的每一位，拼音數字間有 1 空格，但一行中最後一個拼音數字後沒有空格。

輸入樣例：

1234567890987654321123456789

輸出樣例：

yi san wu

Java程式碼實現：

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {

		Scanner input = new Scanner(System.in);
		String inputData = input.next();
		int length = inputData.length();
		String substring = null;
		int sum = 0;
		for(int i =0;i<length;i++){
			substring = inputData.substring(i,i+1);
			int data = Integer.parseInt(substring);
			sum += data;
		}
		Integer sumInt = Integer.valueOf(sum);
		String sumString = sumInt.toString();
		int sumLen = sumString.length();
		StringBuffer result = new StringBuffer();
		String transform = "";
		for(int i = 0;i<sumLen;i++){
			transform = transform(sumString.substring(i,i+1));
			if(i == sumLen-1){
				transform = transform.trim();
			}
			result.append(transform);
		}
		System.out.println(result);
	}
	
	
	public static String transform(String data){
		String chinese = "";
		switch (data) {
		case "0":
			chinese ="ling ";
			break;
		case "1":
			chinese = "yi ";
			break;
		case "2":
			chinese = "er ";
			break;
		case "3":
			chinese = "san ";
			break;
		case "4":
			chinese = "si ";
			break;
		case "5":
			chinese = "wu ";
			break;
		case "6":
			chinese = "liu ";
			break;
		case "7":
			chinese = "qi ";
			break;
		case "8":
			chinese = "ba ";
			break;
		case "9":
			chinese = "jiu ";
			break;
		default:
			break;
		}
		return chinese;
	}

}