1027 Colors in Mars （20 分）

People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.

Input Specification:

Each input file contains one test case which occupies a line containing the three decimal color values.

Output Specification:

For each test case you should output the Mars RGB value in the following format: first output #, then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a 0

Sample Input:

15 43 71

Sample Output:

#123456

注意0

程式碼：

#include<bits/stdc++.h>
using namespace std;
int main()
{
	int a,b,c;
	cin>>a>>b>>c;
	string x = "",y ="",z ="";
	cout<<"#";
	while(a != 0){
		int gg = a % 13;
		a = a / 13;
		if(gg >= 10){
			x += 'A' + gg - 10; 
		}else  
			x += gg + '0';
	}
	reverse(x.begin(),x.end());
	int k = 2 - x.length();
	for(int i = 1; i <= k ; i++)
		cout<<"0";
	cout<<x;
	while(b != 0){
		int gg = b % 13;
		b = b / 13;
		if(gg >= 10){
			y += 'A' + gg - 10; 
		}else  
			y += gg + '0';
	}
	reverse(y.begin(),y.end());
	k = 2 - y.length();
	for(int i = 1; i <= k ; i++)
		cout<<"0";
	cout<<y;
	while(c != 0){
		int gg = c % 13;
		c = c / 13;
		if(gg >= 10){
			z += 'A' + gg - 10; 
		}else  
			z += gg + '0';
	}
	reverse(z.begin(),z.end());
	k = 2 - z.length();
	for(int i = 1; i <= k ; i++)
		cout<<"0";
	cout<<z<<endl;
	return 0;
}