1058 A+B in Hogwarts (20 分)
阿新 • • 發佈:2018-12-31
If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of Galleon.Sickle.Knut
Galleon
is an integer in [0,107], Sickle
is an integer in [0, 17), and Knut
is an integer in [0, 29)).
Input Specification:
Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.
Output Specification:
For each test case you should output the sum of A and B in one line, with the same format as the input.
Sample Input:
3.2.1 10.16.27
Sample Output:
14.1.28
答案如下:
#include<iostream> #include<string> #include<algorithm> #include<vector> #include<stack> using namespace std; struct A { int a[3] = { 0 }; }t[2]; int main() { A c; for (int i = 0; i < 2; i++) { for (int j = 0; j < 3; j++) { cin >> t[i].a[j]; getchar(); c.a[j] += t[i].a[j]; } } for (int i = 2; i >= 0; i--) { if (i ==2 && c.a[i] >= 29) { c.a[1]++; c.a[2] -= 29; } else if (i == 1 && c.a[i] >= 17) { c.a[0]++; c.a[1] -= 17; } } cout << c.a[0] << "." << c.a[1] << "." << c.a[2] << endl; return 0; }