本場詳細題解見：https://blog.csdn.net/xiang_6/article/details/83549528

題意&思路見上述連結

#include<bits/stdc++.h>

using namespace std;

#define out fflush(stdout)
#define fast ios::sync_with_stdio(0),cin.tie(0);

#define FI first
#define SE second

typedef long long ll;
typedef pair<int,int> P;

const int maxn = 2000 + 7;
const int INF = 0x3f3f3f3f;

int n, m;
int a[maxn];
map<int,int> mp;
queue<P> qu;

int main() {
    scanf("%d%d", &n, &m);
    int t_ = n / m;
    for(int i = 1; i <= n; ++i) {
        scanf("%d", &a[i]);
        mp[a[i]]++;
    }
    for(int i = 1; i <= m; ++i) {
        int t = mp[i];
        if(t < t_) {
            qu.push(P(i, t_-t));
        }
    }
    int ans = 0;
    while(!qu.empty()) {
        P t = qu.front(); qu.pop();
        bool ok = 0;
        for(int i = 1; i <= n; ++i) {
            if(a[i] > m) {
                a[i] = t.FI;
                if(t.SE > 1) {
                    qu.push(P(t.FI, t.SE-1));
                }
                ok = 1;
                ans++;
                break;
            }
        }
        if(ok) continue;
        for(int i = 1; i <= n; ++i) {
            if(mp[a[i]] > t_) {
                mp[a[i]]--;
                a[i] = t.FI;
                if(t.SE > 1) {
                    qu.push(P(t.FI, t.SE-1));
                }
                ans++;
                break;
            }
        }
    }
//    for(int i = 1; i <= n; ++i) {
//        if(a[i] > m) {
//            a[i] = 1;
//            ans++;
//        }
//    }


    printf("%d %d\n", t_, ans);
    for(int i = 1; i <= n; ++i) {
        printf("%d%c", a[i], (i == n ? '\n' : ' '));
    }


    return 0;
}