[Swift]LeetCode130. 被圍繞的區域 | Surrounded Regions
阿新 • • 發佈:2018-11-15
Given a 2D board containing 'X' and 'O' (the letter O), capture all regions surrounded by 'X'.
A region is captured by flipping all 'O's into 'X's in that surrounded region.
Example:
X X X X X O O X X X O X X O X X
After running your function, the board should be:
X X X X X X X X X X X X X O X X
Explanation:
Surrounded regions shouldn’t be on the border, which means that any 'O' on the border of the board are not flipped to 'X'. Any 'O' that is not on the border and it is not connected to an 'O' on the border will be flipped to 'X'
給定一個二維的矩陣,包含 'X' 和 'O'(字母 O)。
找到所有被 'X' 圍繞的區域,並將這些區域裡所有的 'O' 用 'X' 填充。
示例:
X X X X X O O X X X O X X O X X
執行你的函式後,矩陣變為:
X X X X X X X X X X X X X O X X
解釋:
被圍繞的區間不會存在於邊界上,換句話說,任何邊界上的 'O' 都不會被填充為 'X'。 任何不在邊界上,或不與邊界上的 'O' 相連的 'O' 最終都會被填充為 'X'。如果兩個元素在水平或垂直方向相鄰,則稱它們是“相連”的。
52ms
1 class Solution { 2 func solve(_ board: inout [[Character]]) { 3 let h = board.count 4 guard h > 2 else { return } 5 6 let w = board[0].count 7 guard w > 2 else { return } 8 9 for i in 0..<h { 10 mark(&board, i, 0) 11 mark(&board, i, w - 1) 12 } 13 14 for j in 0..<w { 15 mark(&board, 0, j) 16 mark(&board, h - 1, j) 17 } 18 19 for i in 0..<h { 20 for j in 0..<w { 21 if board[i][j] == "O" { 22 board[i][j] = "X" 23 } else if board[i][j] == "T" { 24 board[i][j] = "O" 25 } 26 } 27 } 28 } 29 30 func mark(_ board: inout [[Character]], _ i: Int, _ j: Int) { 31 guard i >= 0 && i < board.count else { return } 32 guard j >= 0 && j < board[i].count else { return } 33 guard board[i][j] == "O" else { return } 34 35 board[i][j] = "T" 36 37 mark(&board, i - 1, j) 38 mark(&board, i + 1, j) 39 mark(&board, i, j - 1) 40 mark(&board, i, j + 1) 41 } 42 }
56ms
1 class Solution { 2 func solve(_ board: inout [[Character]]) { 3 for i in 0..<board.count { 4 for j in 0..<board[i].count { 5 if (i == 0 || i == board.count - 1 || j == 0 || j == board[i].count - 1) && board[i][j] == "O" { 6 dfs(&board, i, j) 7 } 8 9 } 10 } 11 for i in 0..<board.count { 12 for j in 0..<board[i].count { 13 if board[i][j] == "O" { 14 board[i][j] = "X" 15 } 16 if board[i][j] == "Y" { 17 board[i][j] = "O" 18 } 19 } 20 } 21 } 22 private func dfs(_ board: inout [[Character]], _ i: Int, _ j: Int) { 23 if board[i][j] == "O" { 24 25 board[i][j] = "Y" 26 if i > 0 && board[i - 1][j] == "O" { 27 dfs(&board, i - 1, j) 28 } 29 30 if j < board[i].count - 1 && board[i][j + 1] == "O" { 31 dfs(&board, i, j + 1) 32 } 33 34 if i < board.count - 1 && board[i + 1][j] == "O" { 35 dfs(&board, i + 1, j) 36 } 37 38 if j > 0 && board[i][j - 1] == "O" { 39 dfs(&board, i, j - 1) 40 } 41 } 42 } 43 }
60ms
1 class Solution { 2 func solve(_ board: inout [[Character]]) { 3 guard board.count > 0 && board[0].count > 0 else { 4 return 5 } 6 7 let countRow = board.count - 1 8 let countCol = board[0].count - 1 9 10 var visited = [[Bool]](repeating:[Bool](repeating: false, count: countCol+1), count: countRow+1) 11 var boarder0Indexs = [(Int,Int)]() 12 13 let direction = [(-1,0),(1,0),(0,-1),(0,1)] // top bot left right 14 15 for row in 0...countRow { 16 for col in 0...countCol { 17 if row == 0 || col == 0 || row == countRow || col == countCol { 18 if board[row][col] == "O" { 19 board[row][col] = "B" 20 boarder0Indexs.append((row,col)) 21 } 22 } 23 } 24 } 25 26 for item in boarder0Indexs { 27 let row = item.0 28 let col = item.1 29 30 var tempQueue = [(Int,Int)]() 31 tempQueue.append(item) 32 33 //bfs 34 while (!tempQueue.isEmpty) { 35 let count = tempQueue.count 36 for _ in 0..<count { 37 let curItem = tempQueue.removeFirst() 38 let curRow = curItem.0 39 let curCol = curItem.1 40 //check adjacent cells 41 for dirt in direction { 42 let nextLevelRow = curRow + dirt.0 43 let nextLevelCol = curCol + dirt.1 44 //make sure not out of bounce 45 if nextLevelRow <= countRow && nextLevelRow >= 0 && nextLevelCol <= countCol && nextLevelCol >= 0 { 46 if !visited[nextLevelRow][nextLevelCol] { 47 if board[nextLevelRow][nextLevelCol] == "O" { 48 board[nextLevelRow][nextLevelCol] = "B" 49 tempQueue.append((nextLevelRow,nextLevelCol)) 50 } 51 visited[nextLevelRow][nextLevelCol] = true 52 } 53 } 54 } 55 } 56 } 57 } 58 for i in 0...countRow { 59 for j in 0...countCol { 60 if board[i][j] == "B" { 61 board[i][j] = "O" 62 } else if board[i][j] == "O" { 63 board[i][j] = "X" 64 } 65 } 66 } 67 } 68 }
80ms
1 class Solution { 2 func solve(_ board: inout [[Character]]) { 3 for i in 0..<board.count{ 4 for j in 0..<board[0].count{ 5 if (i==0 || i == board.count - 1 || j == 0 || j == board[0].count - 1) && board[i][j] == "O" { 6 board[i][j] = "M" 7 connected(i, j, &board) 8 } 9 } 10 } 11 for i in 0..<board.count{ 12 for j in 0..<board[0].count{ 13 if board[i][j] == "O" { 14 board[i][j] = "X" 15 } 16 else if board[i][j] == "M" { 17 board[i][j] = "O" 18 } 19 } 20 } 21 } 22 private func connected(_ i : Int, _ j : Int, _ board: inout [[Character]]){ 23 if i-1 > 0 && board[i-1][j] == "O" { 24 board[i-1][j] = "M" 25 connected(i-1, j, &board) 26 } 27 if i+1 < board.count-1 && board[i+1][j] == "O" { 28 board[i+1][j] = "M" 29 connected(i+1, j, &board) 30 } 31 if j-1 > 0 && board[i][j-1] == "O" { 32 board[i][j-1] = "M" 33 connected(i, j-1, &board) 34 } 35 if j+1 < board[i].count-1 && board[i][j+1] == "O" { 36 board[i][j+1] = "M" 37 connected(i, j+1, &board) 38 } 39 } 40 }
176ms
1 let X = Character("X") 2 let O = Character("O") 3 4 class Solution { 5 6 func solve(_ board: inout [[Character]]) { 7 guard let columnCount = board.first?.count else { 8 return 9 } 10 let rowCount = board.count 11 let uf = UnionFind(rowCount: rowCount, columnCount: columnCount) 12 13 board.enumerated().forEach { i, row in 14 row.enumerated().forEach { j, item in 15 guard item == O else { 16 return 17 } 18 19 if i == 0 || i == rowCount - 1 || j == 0 || j == columnCount - 1 { 20 uf.open(i, j) 21 } 22 23 // top 24 if i > 0 && board[i - 1][j] == O { 25 uf.union(i, j, i - 1, j) 26 } 27 28 // bottom 29 if i < rowCount - 1 && board[i + 1][j] == O { 30 uf.union(i, j, i + 1, j) 31 } 32 33 // left 34 if j > 0 && board[i][j - 1] == O { 35 uf.union(i, j, i, j - 1) 36 } 37 38 // right 39 if j < columnCount - 1 && board[i][j + 1] == O { 40 uf.union(i, j, i, j + 1) 41 } 42 } 43 } 44 45 for i in 0..<rowCount { 46 for j in 0..<columnCount where board[i][j] == O { 47 if !uf.isOpen(i, j) { 48 board[i][j] = X 49 } 50 } 51 } 52 } 53 54 } 55 56 class UnionFind { 57 58 var parent: [Int] 59 var sizes: [Int] 60 61 private let rowCount: Int 62 private let columnCount: Int 63 64 private var opened: [Bool] 65 66 init(rowCount: Int, columnCount: Int) { 67 self.rowCount = rowCount 68 self.columnCount = columnCount 69 70 let count = rowCount * columnCount 71 72 sizes = Array(repeating: 1, count: count) 73 parent = Array(repeating: 0, count: count) 74 opened = Array(repeating: false, count: count) 75 76 for i in 0..<count { 77 parent[i] = i 78 } 79 } 80 81 func isOpen(_ i: Int, _ j: Int) -> Bool { 82 return opened[find(i, j)] 83 } 84 85 func open(_ i: Int, _ j: Int) { 86 let index = calculateIndex(i, j) 87 opened[index] = true 88 } 89 90 func union(_ li: Int, _ lj: Int, _ ri: Int, _ rj: Int) { 91 let rootLeft = find(li, lj) 92 let rootRight = find(ri, rj) 93 94 if li == 0 || li == rowCount - 1 || lj == 0 || lj == columnCount - 1 { 95 open(li, lj) 96 } 97 if ri == 0 || ri == rowCount - 1 || rj == 0 || rj == columnCount - 1 { 98 open(ri, rj) 99 } 100 101 if rootLeft == rootRight { 102 return 103 } 104 105 if opened[rootLeft] { 106 parent[rootRight] = parent[rootLeft] 107 sizes[rootLeft] += sizes[rootRight] 108 return 109 } 110 if opened[rootRight] { 111 parent[rootLeft] = parent[rootRight] 112 sizes[rootRight] += sizes[rootLeft] 113 return 114 } 115 116 if sizes[rootLeft] > sizes[rootRight] { 117 parent[rootRight] = parent[rootLeft] 118 sizes[rootLeft] += sizes[rootRight] 119 } else { 120 parent[rootLeft] = parent[rootRight] 121 sizes[rootRight] += sizes[rootLeft] 122 } 123 } 124 125 func find(_ i: Int, _ j: Int) -> Int { 126 var index = calculateIndex(i, j) 127 while index != parent[index] { 128 parent[index] = parent[parent[index]] 129 index = parent[index] 130 } 131 return index 132 } 133 134 private func calculateIndex(_ i: Int, _ j: Int) -> Int { 135 return i * columnCount + j 136 } 137 }
316ms
1 class Solution { 2 func solve(_ board: inout [[Character]]) { 3 for i in 0..<board.count 4 { 5 for j in 0..<board[i].count 6 { 7 if (i == 0 || i == board.count - 1 || j == 0 || j == board[i].count - 1) && board[i][j] == "O" 8 { 9 solveDFS(&board, i, j) 10 } 11 } 12 } 13 for i in 0..<board.count 14 { 15 for j in 0..<board[i].count 16 { 17 if board[i][j] == "O" {board[i][j] = "X"} 18 if board[i][j] == "$" {board[i][j] = "O"} 19 } 20 } 21 } 22 23 func solveDFS(_ board: inout [[Character]],_ i:Int,_ j:Int) 24 { 25 if board[i][j] == "O" 26 { 27 board[i][j] = "$" 28 if i > 0 && board[i - 1][j] == "O" 29 { 30 solveDFS(&board, i - 1, j) 31 } 32 if j < board[i].count - 1 && board[i][j + 1] == "O" 33 { 34 solveDFS(&board, i, j + 1) 35 } 36 if i < board.count - 1 && board[i + 1][j] == "O" 37 { 38 solveDFS(&board, i + 1, j) 39 } 40 if j > 1 && board[i][j - 1] == "O" 41 { 42 solveDFS(&board, i, j - 1) 43 } 44 } 45 } 46 }
