Flutter 擴充套件NestedScrollView (二)列表滾動同步解決
接著上篇,沒看上篇的小夥伴建議先看下上篇,免得斷片中。。
我繼續講下第2個問題的解決方案。
當在裡面放上tabview,並且tab是快取狀態的時候,會出現滾動會互相影響的問題
上篇我們說到 在我們的主角NestedScrollView當中,有2個ScrollController.
class _NestedScrollController extends ScrollController {
_NestedScrollController(
this.coordinator, {
double initialScrollOffset = 0.0,
String debugLabel,
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一個是inner,一個outer。 outer是負責headerSliverBuilder裡面的滾動widgets inner是負責body裡面的滾動widgets 當outer滾動到底了之後,就會看看inner裡面是否有能滾動的東東,開始滾動
Tabview是在body裡面,這裡我們肯定需要對inner進行處理。 首先我們要明白,NestedScrollView是怎麼處理outer和inner的關係的。
找到這個_NestedScrollCoordinator 的applyUserOffset方法中處理了整個NestedScrollView的滑動處理
@override
void applyUserOffset(double delta) {
updateUserScrollDirection(delta > 0.0 ? ScrollDirection.forward : ScrollDirection.reverse);
assert(delta != 0.0);
if (_innerPositions.isEmpty) {
_outerPosition.applyFullDragUpdate(delta);
} else if (delta < 0.0) {
// dragging "up"
// TODO(ianh): prioritize first getting rid of overscroll, and then the
// outer view, so that the app bar will scroll out of the way asap.
// Right now we ignore overscroll. This works fine on Android but looks
// weird on iOS if you fling down then up. The problem is it's not at all
// clear what this should do when you have multiple inner positions at
// different levels of overscroll.
final double innerDelta = _outerPosition.applyClampedDragUpdate(delta);
if (innerDelta != 0.0) {
for (_NestedScrollPosition position in _innerPositions)
position.applyFullDragUpdate(innerDelta);
}
} else {
// dragging "down" - delta is positive
// prioritize the inner views, so that the inner content will move before the app bar grows
double outerDelta = 0.0; // it will go positive if it changes
final List<double> overscrolls = <double>[];
final List<_NestedScrollPosition> innerPositions = _innerPositions.toList();
for (_NestedScrollPosition position in innerPositions) {
final double overscroll = position.applyClampedDragUpdate(delta);
outerDelta = math.max(outerDelta, overscroll);
overscrolls.add(overscroll);
}
if (outerDelta != 0.0)
outerDelta -= _outerPosition.applyClampedDragUpdate(outerDelta);
// now deal with any overscroll
for (int i = 0; i < innerPositions.length; ++i) {
final double remainingDelta = overscrolls[i] - outerDelta;
if (remainingDelta > 0.0)
innerPositions[i].applyFullDragUpdate(remainingDelta);
}
}
}
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Iterable<_NestedScrollPosition> get _innerPositions {
return _innerController.nestedPositions;
}
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看到_innerPositions是我們要關注的東西,通過debug,我發現,如果tabview的每個tab做了快取,那麼每個tab裡面列表的ScrollPosition將一直快取在這個ScrollController裡面。 當tab到tabview的某個tab的時候,ScrollController將會將這ScrollPosition attach 上,如果沒有快取,將會在離開的時候detach掉。
@override
void attach(ScrollPosition position) {
assert(position is _NestedScrollPosition);
super.attach(position);
coordinator.updateParent();
coordinator.updateCanDrag();
position.addListener(_scheduleUpdateShadow);
_scheduleUpdateShadow();
}
@override
void detach(ScrollPosition position) {
assert(position is _NestedScrollPosition);
position.removeListener(_scheduleUpdateShadow);
super.detach(position);
_scheduleUpdateShadow();
}
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真相只有一個。。是的。。可以說。。造成快取tabview的各個tab裡面的列表互相影響的原因,是因為歪果仁說: as design(我就是這樣設計的,不服嗎).
按照我的思想啊,我滾動的時候。當然只想影響當前顯示的這個列表啊。這不科學啊。。
找到原因找到原理,一切就都好解決了。現在的關鍵點在於,我怎麼能知道顯示對應的是哪個列表的?!
這個問題問了很多人。。也查找了好久都沒找到好的方式去獲取當前 啟用的 列表對應的 ScrollPosition。。終於我只能想到一個 workaround。暫時解決這個問題。
提供一個容器,把inner裡面的滾動列表包裹起來,並且設定它的tab 的唯一key
//pack your inner scrollables which are in NestedScrollView body
//so that it can find the active scrollable
//compare with NestedScrollViewInnerScrollPositionKeyBuilder
class NestedScrollViewInnerScrollPositionKeyWidget extends StatefulWidget {
final Key scrollPositionKey;
final Widget child;
NestedScrollViewInnerScrollPositionKeyWidget(
this.scrollPositionKey, this.child);
@override
_NestedScrollViewInnerScrollPositionKeyWidgetState createState() =>
_NestedScrollViewInnerScrollPositionKeyWidgetState();
}
class _NestedScrollViewInnerScrollPositionKeyWidgetState
extends State<NestedScrollViewInnerScrollPositionKeyWidget> {
@override
Widget build(BuildContext context) {
return widget.child;
}
// @override
// void didChangeDependencies() {
// // TODO: implement didChangeDependencies
// //print("didChangeDependencies"+widget.scrollPositionKey.toString());
// super.didChangeDependencies();
// }
//
// @override
// void didUpdateWidget(NestedScrollViewInnerScrollPositionKeyWidget oldWidget) {
// // TODO: implement didUpdateWidget
// //print("didUpdateWidget"+widget.scrollPositionKey.toString()+oldWidget.scrollPositionKey.toString());
// super.didUpdateWidget(oldWidget);
// }
}
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然後在剛才attach方法中通過先祖NestedScrollViewInnerScrollPositionKeyWidget
@override
void attach(ScrollPosition position) {
assert(position is _NestedScrollPosition);
super.attach(position);
attachScrollPositionKey(position as _NestedScrollPosition);
coordinator.updateParent();
coordinator.updateCanDrag();
position.addListener(_scheduleUpdateShadow);
_scheduleUpdateShadow();
}
@override
void detach(ScrollPosition position) {
assert(position is _NestedScrollPosition);
position.removeListener(_scheduleUpdateShadow);
super.detach(position);
detachScrollPositionKey(position as _NestedScrollPosition);
_scheduleUpdateShadow();
}
void attachScrollPositionKey(_NestedScrollPosition position) {
if (position != null && scrollPositionKeyMap != null) {
var key = position.setScrollPositionKey();
if (key != null) {
if (!scrollPositionKeyMap.containsKey(key)) {
scrollPositionKeyMap[key] = position;
} else if (scrollPositionKeyMap[key] != position) {
//in demo ,when tab to tab03, the tab02 key will be tab00 at first
//then it become tab02.
//this is not a good solution
position.clearScrollPositionKey();
Future.delayed(Duration(milliseconds: 500), () {
attachScrollPositionKey(position);
});
}
}
}
}
void detachScrollPositionKey(_NestedScrollPosition position) {
if (position != null &&
scrollPositionKeyMap != null &&
position.key != null &&
scrollPositionKeyMap.containsKey(position.key)) {
scrollPositionKeyMap.remove(position.key);
position.clearScrollPositionKey();
}
}
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獲取先祖NestedScrollViewInnerScrollPositionKeyWidget方法
Key setScrollPositionKey() {
//if (haveDimensions) {
final type = _typeOf<NestedScrollViewInnerScrollPositionKeyWidget>();
NestedScrollViewInnerScrollPositionKeyWidget keyWidget =
(this.context as ScrollableState)
?.context
?.ancestorWidgetOfExactType(type);
_key = keyWidget?.scrollPositionKey;
return _key;
}
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找到這個_NestedScrollCoordinator 的applyUserOffset方法中我們現在要替換掉 _innerPositions為_currentInnerPositions
Iterable<_NestedScrollPosition> get _innerPositions {
//return _currentPositions;
return _innerController.nestedPositions;
}
Iterable<_NestedScrollPosition> get _currentInnerPositions {
return _innerController
.getCurrentNestedPositions(innerScrollPositionKeyBuilder);
}
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getCurrentNestedPositions裡面的程式碼
Iterable<_NestedScrollPosition> getCurrentNestedPositions(
NestedScrollViewInnerScrollPositionKeyBuilder
innerScrollPositionKeyBuilder) {
if (innerScrollPositionKeyBuilder != null &&
scrollPositionKeyMap.length > 1) {
var key = innerScrollPositionKeyBuilder();
if (scrollPositionKeyMap.containsKey(key)) {
return <_NestedScrollPosition>[scrollPositionKeyMap[key]];
} else {
return nestedPositions;
}
}
return nestedPositions;
}
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SampeCode
extended.NestedScrollView(
headerSliverBuilder: (c, f) {
return _buildSliverHeader(primaryTabBar);
},
//
pinnedHeaderSliverHeightBuilder: () {
return pinnedHeaderHeight;
},
innerScrollPositionKeyBuilder: () {
var index = "Tab";
if (primaryTC.index == 0) {
index +=
(primaryTC.index.toString() + secondaryTC.index.toString());
} else {
index += primaryTC.index.toString();
}
return Key(index);
},
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這裡由你自己協定tab key。。我這裡是一級tab+二級tab的index。。比如 Tab00代表一級tab第一個下面的二級tab的第一個。
定義tab裡面的列表的時候如下,比如第一個tab下面的二級tab的第一個列表,那麼它的key 為Tab00.
return extended.NestedScrollViewInnerScrollPositionKeyWidget(
Key("Tab00"),
// myRefresh.RefreshIndicator(
// child:
ListView.builder(
itemBuilder: (c, i) {
return Container(
//decoration: BoxDecoration(border: Border.all(color: Colors.orange,width: 1.0)),
alignment: Alignment.center,
height: 60.0,
child: Text(widget.tabKey.toString() + ": List$i"),
);
},
itemCount: 100)
//,
//onRefresh: onRefresh,
// )
);
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最後放上 Github extended_nested_scroll_view,如果你有更好的方式解決這個問題或者有什麼不明白的地方,都請告訴我,由衷感謝。