入坑codewars第二天-Basic Mathematical Operations、Ones and Zeros
一、題目
需要實現 +對應加法
需要實現 -對應減法
……
以此類推
二、求解
簡單的if語句
二、題二
題意就是：將列表中的數字看成一串二進位制然後轉成十進位制數
我的思路是：先把列表顛倒，這裡注意列表a，a.reverse()就直接把a顛倒了；因為二進位制是從右到左讀,因此我先顛倒從左往右方便計算。
（1）先顛倒列表：
（2）迴圈用列表數字乘以2^n
（3）依次相加
程式碼如下：
def binary_array_to_number(arr):
arr.reverse()
sum1=0
i=0
for x in arr:
sum1=sum1+(2**i)*x
i=i+1
return sum1
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