文字處理【1.1.1】-判斷字串型別並返回相應型別
阿新 • • 發佈:2018-11-25
def formats(st): if '.' in st or 'e' in st or 'E' in st: try: return float(st) except: return st else: try: return int(st) except: return st a1 = formats('1') a2 = formats('3.4') a3 = formats('1.03E+08') a4 = formats('wujiadong') print('a1:',a1,type(a1)) print('a2:',a2,type(a2)) print('a3:',a3,type(a3)) print('a4:',a4,type(a4)) 執行結果如下: a1: 1 <class 'int'> a2: 3.4 <class 'float'> a3: 103000000.0 <class 'float'> a4: wujiadong <class 'str'>