洛谷 #1955. 程式自動分析
阿新 • • 發佈:2018-11-26
題意
有n個表示式 != 或 =,判斷是否矛盾
題解
離散化+並查集
除錯記錄
f陣列開得太小
#include <cstdio>
#include <cstring>
#include <algorithm>
#define maxn 100005
using namespace std;
int T, n, f[maxn << 2];
struct node{
int x, y, opt;
}q[maxn];
int getf(int x){
return (x == f[x]) ? x : (f[x] = getf(f[x]));
}
int arr[maxn << 2];
int main(){
scanf("%d", &T);
while (T--){
memset(arr, 0, sizeof arr);
scanf("%d", &n);
for (int i = 1; i <= n; i++){
scanf("%d%d%d", &q[i].x, &q[i].y, &q[i].opt);
arr[++arr[0]] = q[i].x, arr[++arr[0]] = q[i].y;
}
sort(arr + 1, arr + arr[0] + 1);
int m = n;
for (int i = 1; i <= n; i++){
m = max(m, (q[i].x = lower_bound(arr + 1, arr + arr[0] + 1, q[i].x) - arr));
m = max(m, (q[i].y = lower_bound(arr + 1, arr + arr[0] + 1, q[i].y) - arr));
}
for (int i = 1; i <= m; i++) f[i] = i;
for (int i = 1; i <= n; i++)
if (q[i].opt)
if (getf(q[i].x) != getf(q[i].y)) f[getf(q[i].x)] = getf(q[i].y);
bool flag = false;
for (int i = 1; i <= n; i++)
if (!q[i].opt)
if (getf(q[i].x) == getf(q[i].y)){
printf("NO\n");
flag = true;
break;
}
if (!flag) printf("YES\n");
}
return 0;
}