python leetcode 435. Non-overlapping Intervals
類似於時刻安排表 最後的列表中每個end應該儘量要小
44ms 100%
class Solution: def eraseOverlapIntervals(self, intervals): """ :type intervals: List[Interval] :rtype: int """ newIn=sorted(intervals,key=lambda intervals:intervals.end) count=0 lastend=None for n in newIn: if lastend==None: lastend=n.end else: if n.end==lastend or n.start<lastend: count+=1 else: lastend=n.end return count
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類似於時刻安排表 最後的列表中每個end應該儘量要小 44ms 100% class Solution: def eraseOverlapIntervals(self, intervals): """ :type intervals: List[I
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