Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

用hashmap記錄陣列元素及其下標 <nums[i], i>

注意返回值要求是下標小的在前面，而從左往右遍歷陣列， 一般在右半部分才能找到相加為target的數，此時的index應該是較的的那個，應該放在第二位，從map中取得的index應該放在第一位。

時間：O(N)，空間：O(N)

class Solution {
    public int[] twoSum(int[] nums, int target) {
        HashMap<Integer, Integer> map = new HashMap<>();
        
 
for(int i = 0; i < nums.length; i++) {
            if(map.containsKey(target - nums[i]))
                return new int[] {map.get(target - nums[i]), i};
            map.put(nums[i], i);
        }
        return null;
    }
}