leetcode Reverse Bits
Reverse Bits 反轉2進位制數
解題思路:每次result+=n&1 取出最右邊的一位,n>>1, result<<=1
public static int reverseBits(int n) {
int result=0;
for(int i=0;i<32;i++){
result+=n&1;
n>>=1;
if(i<31){
result<<=1;
}
}
return result;
}
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