Text Reverse

Problem Description
This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.

Input
Each line will contain two integers A and B. Process to end of file.

Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.

問題簡述：先把兩個數相加，然後把相加後的數對86求餘，判斷餘數是否為零。是0就輸出yes，不是就輸出no。

#include <iostream>
using namespace std;
int main()
{
 int a, b;
 while (cin>>a>>b)
 {
  if ((a + b) % 86 == 0)
   cout << "yes" << endl;
  else cout << "no" << endl;
 }
}