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題目來源 ：http://118.190.20.162/view.page?gpid=T79

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問題描述

答題欄

程式碼示例

C++

#include<iostream>

using namespace std;
int main()
{
	int n,i;
	cin >> n;
	int price[n];
	for(i=0; i<n; i++)
	{
		cin >> price[i];
	}
	cout << (price[0]+price[1])/2 << ' ';
	n--;
	for(i=1; i<n; i++)
	{
		cout << (price[i-1]+price[i]+price[i+1])/3 << ' ';
	}
	cout << (price[n-1]+price[n])/2 << ' ';
	return 0;
}
 

Python： 

import re

n = int(input())
i=1
inp = input()
#print(inp)
t = re.findall('\d+', inp)
#print(t)
p=[]
for i in t:
    p.append(int(i))
#print(p)
print(int((p[0]+p[1])/2), end=' ')
for i in range(1,n-1):
    #print(i)
    print(int((p[i-1]+p[i]+p[i+1])/3), end=' ')
print(int((p[n-1]+p[n-2])/2), end='')