6-1 計算兩個複數之積 (10 分)
阿新 • • 發佈:2018-12-13
6-1 計算兩個複數之積 (10 分)
本題要求實現一個計算複數之積的簡單函式。
函式介面定義:
struct complex multiply(struct complex x, struct complex y);
其中struct complex是複數結構體,其定義如下:
struct complex{
int real;
int imag;
};
裁判測試程式樣例:
#include <stdio.h>
struct complex{
int real;
int imag;
};
struct complex multiply(struct complex x, struct complex y);
int main()
{
struct complex product, x, y;
scanf("%d%d%d%d", &x.real, &x.imag, &y.real, &y.imag);
product = multiply(x, y);
printf("(%d+%di) * (%d+%di) = %d + %di\n",
x.real, x.imag, y.real, y.imag, product.real, product.imag);
return 0;
}
/* 你的程式碼將被嵌在這裡 /
輸入樣例:
3 4 5 6
輸出樣例:
(3+4i) * (5+6i) = -9 + 38
程式碼:
struct complex multiply(struct complex x, struct complex y)
{
struct complex a;
a.real = x.real
a.imag = x.imagy.real+x.real*y.imag;
return a;
}