Leetcode 6 ZigZag Conversion
阿新 • • 發佈:2018-12-13
The string "PAYPALISHIRING"
is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string s, int numRows);
Example 1:
Input: s = "PAYPALISHIRING", numRows = 3 Output: "PAHNAPLSIIGYIR"
Example 2:
Input: s = "PAYPALISHIRING", numRows = 4 Output: "PINALSIGYAHRPI" Explanation: P I N A L S I G Y A H R P I
class Solution { public String convert(String s, int numRows) { if(s == null || s.length() == 0 || numRows <= 1){ return s; } int len = s.length(); int circle = 2 * numRows - 2; StringBuilder[] sc = new StringBuilder[numRows]; for (int i = 0; i < sc.length; i++) sc[i] = new StringBuilder(); for(int i = 0 ; i < len; i++){ int num = i % circle; if(num < numRows){ char c = s.charAt(i); sc[num].append(c); }else{ sc[circle - num].append(s.charAt(i)); } } StringBuilder ss = new StringBuilder(); for(int i = 0 ; i < numRows ; i++){ ss.append(sc[i]); } return ss.toString(); } }
時間複雜度為O(n),思路是借鑑的牛客上面的,很奇妙,自己手動擼了一遍基本掌握-