leetcode-476
int findComplement(int num) { int move=num; mo|=move>>1; mo|=move>>2; mo|=move>>4; mo|=move>>8; mo|=move>>16; mo|=move>>32; return num^move; }
提交後時間很尷尬,12ms,不確定這個int是多少位的所以直接給了個32位。
說下思路,一個數與它有效位全為1的數異或就能得到它的補數。所以得到全為1數是個關鍵,從有效位最高位向後一直移位就能得到全為1的數,按照int位向後移位就好了。
leetcode-476
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