請使用迭代查詢一個list中最小和最大值,並返回一個tuple(Python)
阿新 • • 發佈:2018-12-13
from collections import Iterable, Iterator def g(): yield 1 yield 2 yield 3 print('Iterable? [1, 2, 3]:', isinstance([1, 2, 3], Iterable)) print('Iterable? \'abc\':', isinstance('abc', Iterable)) print('Iterable? 123:', isinstance(123, Iterable)) print('Iterable? g():', isinstance(g(), Iterable)) print('Iterator? [1, 2, 3]:', isinstance([1, 2, 3], Iterator)) print('Iterator? iter([1, 2, 3]):', isinstance(iter([1, 2, 3]), Iterator)) print('Iterator? \'abc\':', isinstance('abc', Iterator)) print('Iterator? 123:', isinstance(123, Iterator)) print('Iterator? g():', isinstance(g(), Iterator)) # iter list: print('for x in [1, 2, 3, 4, 5]:') for x in [1, 2, 3, 4, 5]: print(x) print('for x in iter([1, 2, 3, 4, 5]):') for x in iter([1, 2, 3, 4, 5]): print(x) print('next():') it = iter([1, 2, 3, 4, 5]) print(next(it)) print(next(it)) print(next(it)) print(next(it)) print(next(it)) d = {'a': 1, 'b': 2, 'c': 3} # iter each key: print('iter key:', d) for k in d.keys(): print('key:', k) # iter each value: print('iter value:', d) for v in d.values(): print('value:', v) # iter both key and value: print('iter item:', d) for k, v in d.items(): print('item:', k, v) # iter list with index: print('iter enumerate([\'A\', \'B\', \'C\']') for i, value in enumerate(['A', 'B', 'C']): print(i, value) # iter complex list: print('iter [(1, 1), (2, 4), (3, 9)]:') for x, y in [(1, 1), (2, 4), (3, 9)]: print(x, y) #函式尋找最大最小值 def findmaxmin(L): if L!=[]: max=L[0] min=L[0] for l in L: if max<l: max=l if min>l: min=l return (min,max) else: return(None,None) L=[1,9,4,5] print(findmaxmin(L))
這裡將列表生成式和生成器的主要用法都概括了!