Leetcode 445. Add Two Numbers II
阿新 • • 發佈:2018-12-14
文章作者:Tyan 部落格:noahsnail.com | CSDN | 簡書
1. Description
2. Solution
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
stack<int> s1, s2;
ListNode* current = l1;
while(current) {
s1.push(current->val);
current = current->next;
}
current = l2;
while(current) {
s2.push(current->val);
current = current-> next;
}
int carry = 0;
int sum = 0;
ListNode* pre = nullptr;
while(!s1.empty() || !s2.empty()) {
sum = 0;
if(!s1.empty()) {
sum += s1.top();
s1.pop();
}
if(!s2.empty()) {
sum + = s2.top();
s2.pop();
}
sum += carry;
carry = sum>9?1:0;
current = new ListNode(sum % 10);
current->next = pre;
pre = current;
}
if(carry) {
current = new ListNode(1);
current->next = pre;
}
return current;
}
};