34. Find First and Last Position of Element in Sorted Array
題意：
一個有序陣列中有重複元素，返回第一個和最後一個target的下標。要求O（logN）。
思路：
沒什麼好說的，還是二分法。
vector<int> searchRange(vector<int>& nums, int target) { int l = 0, r = nums.size() - 1, mid, sz = nums.size(), get = -1; if (sz == 0) return{ -1,-1 }; while (l <= r) { mid = (l + r) / 2; if (nums[mid] == target) { get = mid; break; } else if (nums[mid] > target) r = mid - 1; else l = mid + 1; } if (get == -1) return{ -1,-1 }; int first = get, last = get; while (first >= 1 && nums[first - 1] == nums[first]) --first; while (last <= sz - 2 && nums[last + 1] == nums[last]) ++last; return{ first,last }; }
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