函式根的求法 python
阿新 • • 發佈:2018-12-15
二分法求函式根
import math def bisection(function, a, b): # finds where the function becomes 0 in [a,b] using bolzano start = a end = b if function(a) == 0: # one of the a or b is a root for the function return a elif function(b) == 0: return b elif function(a) * function(b) > 0: # if none of these are root and they are both positive or negative, # then his algorithm can't find the root print("couldn't find root in [a,b]") return else: mid = (start + end) / 2 while abs(start - mid) > 0.0000001: # until we achieve precise equals to 10^-7 if function(mid) == 0: return mid elif function(mid) * function(start) < 0: end = mid else: start = mid mid = (start + end) / 2 return mid def f(x): return math.pow(x, 3) - 2*x - 5 print(bisection(f, 1, 1000))
逐次逼近法
import math def intersection(function,x0,x1): #function is the f we want to find its root and x0 and x1 are two random starting points x_n = x0 x_n1 = x1 while True: x_n2 = x_n1-(function(x_n1)/((function(x_n1)-function(x_n))/(x_n1-x_n))) if abs(x_n2 - x_n1)<0.00001 : return x_n2 x_n=x_n1 x_n1=x_n2 def f(x): return math.pow(x,3)-2*x-5 print(intersection(f,3,3.5))