2018.10.19——10.3定製操作
阿新 • • 發佈:2018-12-16
10.14
[] (const int &a, const int &b) {return a+b;}
答案
#include <iostream>
using namespace std;
int main(int argc, char *[])
{
auto sum = [] (int a, int b) { return a+b;};
cout << sum(1, 1) << endl;
return 0;
}
10.15
include <iostream> using namespace std; int fuc(int a) { auto sum = [a] (int b) {return a+b;}; //沒有給b賦值 return sum; } int main() { cout << fuc(1) << endl; return 0; }
答案
#include <iostream>
using namespace std;
void add(int a)
{
auto sum = [a] (int b) {return a + b;};
cout << sum(1) << endl;
}
int main()
{
add(1);
add(2);
return 0;
}
10.16
void bigies(vector<string> words, vector<string>::size_type sz) { elimdups(words); //將words裡的單詞按字典序排列,刪除重複單詞 // 按長度排序,長度相同的單詞維持字典序 stable_sort(words.begin(), words.end(), [] (const string &a, const string &b) {return a.size < b.size();}); //獲取一個迭代器,指向滿足size() >= sz的元素 auto wc = find_if(words.begin(), words.end(), [sz] (const string &a) {return a.size > sz;}); //計算滿足size >= sz的元素的數目 auto count = words.end() - wc; cout << count <<" "<< make_plural(count, "word", "s") << " of length " << sz << " or lenger " << endl; //列印長度大於等於給定值的單詞,每個單詞後接一個空格 for_each(wc. words.end(), [] (const string &s) { cout << s << " ";}); cout << endl; }