Comparable介面實現集合的排序
阿新 • • 發佈:2018-12-16
1.讓需要排序的物件實現Comparable介面,並重寫compareTo方法
public class Student implements Comparable<Student> { //泛型為需要排序的物件
private int age;
private String name; private int score; public int getAge() { return age; } public voidsetAge(int age) { this.age = age; } public String getName() { return name; } public void setName(String name) { this.name = name; } public int getScore() { return score; } public void setScore(int score) { this.score = score; }public Student(int age, String name, int score) { super(); this.age = age; this.name = name; this.score = score; }
@Override public int compareTo(Student other) { //引數為需要排序的物件 return score-other.getScore(); //表示通過分數score欄位進行排序 } }
2.構造需要排序的物件的集合,並呼叫Collections.sort()方法對集合中元素進行排序:
public class CompareTest { public static void main(String[] args) { Student s1 = new Student(16, "aa", 44); Student s2 = new Student(18, "bb", 88); Student s3 = new Student(17, "cc", 99); Student s4 = new Student(19, "dd", 66); List<Student> students = Arrays.asList(s1, s2, s3, s4); Collections.sort(students); //對students按score欄位進行排序 for (Student student : students) { System.out.println(student.getScore()); } } }
注意:使用 Collections.sort(students);方法對集合物件進行排序時,集合中的物件必須實現Comparable介面,否則報錯