[leetcode]Count and Say
阿新 • • 發佈:2018-12-19
The count-and-say sequence is the sequence of integers with the first five terms as following:
1. 1 2. 11 3. 21 4. 1211 5. 111221
1
is read off as "one 1"
or 11
.11
is read off as "two 1s"
or 21
.21
is read off as "one 2
, then one 1"
or 1211
.
Given an integer n where 1 ≤ n ≤ 30, generate the n
Note: Each term of the sequence of integers will be represented as a string.
分析:
對於n,找出n-1行相同元素的個數,將個數和相應元素存放在string中即可。
class Solution { public: string countAndSay(int n) { string a="1",temp=""; for(int i=1;i<n;i++) { int t=0; while(t<a.size()) { int num=1;//相同元素的個數 while(a[t]==a[t+1])//若元素相同 { num++; t++; } temp=temp+to_string(num)+a[t];//將元素的個數轉化為字串,與元素一同存入字串 t++; } a=temp; temp=""; } return a; } };