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python machine learning(Apply for KNN Algorithm)

Following is a simple instance of KNN algorithm
Our goal is to build a machine learning model that can learn from the measurement of these irises whose species is known,so that we can predict the species for a new iris.
Because we have measurements for which we know the correct species of iris,this is a supervised learning problem. In this problem,we want to predict one of several options (the species of iris).this is a example of a classification problem.The possible output(different species of iris) are called classes

.Every iris in the dataset belong to one of three classed,so the problem is a three-class classification problem.
The desired output for single data point(an iris) is the species of this flower.For a particular data point,the species it belongs to is called lable

Here is the code

#iris.py
import numpy as
np import pandas as pd from sklearn.model_select import train_test_split from sklearn.datasets import load_iris from sklearn.neighbors import KNeighborsClassifier iris_dataset = load_iris() #split dataset to two part,which is 75% for training,25% for test X_train,X_test,y_train,y_test = train_test_split(
iris_dataset['data'],iris_dataset['target'],random.state=0) #define the knn classifier knn = KNeighborsClassifier(n_neighbors=1) #train the dataset knn.fit(x_train,y_train)

After training,the object knn is built to be a model,we can use it now.
Support that we found an iris in the wild with a sepal(花萼) length of 5 cm,a sepal width of 2.9 cm,a petal(花瓣) length of 1 cm,a petal width of 0.2 cm.
Now let’s predict what species it would be.

#contect to the upper code
X_new = np.array([[5,2.9,1,0.2]])
prediction = knn.prediction(X_new)
print("prediction:{}".format(prediction))
print("predicted target name:{}".format(
		iris_dataset['target_name’][prediction]))

Here is the output

pediction:[0]
predicted target name:['setosa']

Last we should measure how well the model works by computing the accuracy

y_pred = knn.predict(X_test)
print("test set score:{:.2f}".format(np.mean(y_pred==y_test)))

output is

test set score:0.97