python leetcode 260. Single Number III
關鍵是找到a和b第k位上一個為0一個為1，然後再與第k位上為1的異或
class Solution:
def singleNumber(self, nums):
"""
:type nums: List[int]
:rtype: List[int]
"""
a1=a2=0
for n in nums:
a1^=n
k = a1&(~a1+1)
for n in nums:
if n& 相關推薦
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