折半查詢、快速排序
阿新 • • 發佈:2018-12-24
折半查詢
迴圈實現
'''
折半查詢
迴圈實現
'''
def binarySearch(list, key):
low = 0
high = len(list) - 1
while (low <= high): # 迴圈法的判斷條件,就是遞迴法的基線條件
mid = (low + high) // 2
gess = list[mid]
if gess > key:
high = mid - 1
if gess < key:
low = mid + 1
if gess == key:
return mid
return -1
print(binarySearch([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 6))
遞迴實現
# 遞迴實現折半查詢
def binarySearch2(list, low, high, key):
if (low > high): # 遞迴的基線條件
return -1
else:
mid = (low + high) // 2
if (list[mid] == key):
return mid
if (key > list[mid]):
return binarySearch2(list, mid + 1, high, key) # 在序列的後半部分查詢
else:
return binarySearch2(list, low, mid - 1, key) # 在序列的前半部分查詢
print(binarySearch2([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 0, 10, 6))
快速排序
開闢新空間儲存中間結果
'''
快速排序
遞迴實現,分而治之
實現1, 開闢新空間儲存中間結果
實現2, 不開闢多餘空間來儲存中間結果
'''
# 合併陣列
# print([1, 2, 3, 4] + [5, 6, 7, 8])
# 遞迴法快速排序實現1
def qSort(list):
if len(list) < 2: # 基線條件,陣列只有一個元素或者沒有元素是,不需要排序,直接返回
return list
else: # 需要排序的陣列
pivot = list[0]
less = [i for i in list[1:] if i < pivot]
greater = [i for i in list[1:] if i > pivot]
return qSort(less) + [pivot] + qSort(greater)
listA = [40, 30, 20, 25, 60, 10]
print(qSort(listA))
快速排序
分而治之的典型演算法,在遞迴過程中要明確基線條件和遞迴條件
# 遞迴法快速排序實現2
def qSort2(list, left, right):
if left >= right:
return None
else:
bound = getBound(list, left, right)
qSort2(list, left, bound - 1) # 對基準值左側進行排序
qSort2(list, bound + 1, right) # 對基準值右側進行排序
def getBound(list, left, right): # 使用雙指標,參考基準值從兩頭開始挑揀元素
povit = list[left]
while (left < right):
while (left < right and list[right] >= povit):
right -= 1
list[left] = list[right]
while (left < right and list[left] <= povit):
left += 1
list[right] = list[left]
list[left] = povit
return left
print(listA)
qSort2(listA, 0, len(listA) - 1)
print(listA)