# Reverse digits of an integer.
#
# Example1: x = 123, return 321
# Example2: x = -123, return -321
#
# click to show spoilers.
# Note:
# The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows.
# Subscribe to see which companies asked this question.
 
# 輸入一個32位的有符號整數，返回該數字的翻轉部分（不包括符號），如果翻轉之後超出32位的範圍就返回０
class Solution(object):
    def reverse(self, num):
        num = str(num)
        if num[0] == '-':
            num = '-' + num[1:][::-1]
        else:
            num = num[::-1]
        num = int(num)
        if num < -2147483648 or num > 2147483647
 
:
            return 0
else:
            return num

if __name__ == '__main__':
    num = -1235679
s = Solution()
    print(s.reverse(num))