LeetCode240 Search a 2D Matrix II
阿新 • • 發佈:2018-12-26
Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
Integers in each row are sorted in ascending from left to right.
Integers in each column are sorted in ascending from top to bottom.
Example:
Consider the following matrix:
[
[1, 4, 7, 11, 15],
[2, 5, 8, 12, 19],
[3, 6, 9, 16, 22],
[10, 13, 14, 17, 24],
[18, 21, 23, 26, 30]
]
Given target = 5, return true.
Given target = 20, return false.
class Solution { public boolean searchMatrix(int[][] matrix, int target) { if(matrix == null || matrix.length == 0 || matrix[0].length == 0) return false; int x = 0; int y = matrix[0].length - 1; while(x <= matrix.length - 1 && y >= 0){ if(matrix[x][y] == target) return true; else if(matrix[x][y] > target) y--; else x++; } return false; } }