SQL計算時間差並排除週末
阿新 • • 發佈:2018-12-27
CREATE FUNCTION DI_FN_GET_WorkDay (@begin DATETIME , @end DATETIME ) RETURNS int BEGIN DECLARE @i INT , @j INT SET @i = 0 SET @j = 0 IF @end > @begin BEGIN WHILE DATEDIFF(d, DATEADD(d, @i, @begin), @end) <> 0 BEGIN IF DATEPART(weekday, DATEADD(d, @i, @begin)) NOT IN ( 1, 7 ) SET @j = @j + 1 SET @i = @i + 1 END END SELECT @j = ( @j + 1 ) * 24 * 60 - DATEDIFF(Minute, CAST(CONVERT(VARCHAR(10), @begin, 120) AS DATETIME), @begin) - DATEDIFF(Minute, @end, CAST(CONVERT(VARCHAR(10), @end + 1, 120) AS DATETIME)) RETURN @j END
其中可以根據自己需要更改下函式得到對應的小時數,分鐘數或者秒數等