Where else can I find smart people online?(Discussion)
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Where else can I find smart people online?(Discussion)
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HDOJ1796 How many integers can you find(dfs+容斥)
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[容斥原理] hdu 1796 How many integers can you find
pos lcm 一個 每一個 fin memset 而不是 std != 題意: 給一個N。然後給M個數,問1~N-1裏面有多少個數能被這M個數中一個或多個數整除。 思路: 首先要N-- 然後對於每一個數M 事實上1~N-1內能被其整除的 就是有(N-1)/
HDU 1796 How many integers can you find (容斥)
ace return algo 整除 ctype hdu scanf ++ main 題意:給定一個數 n,和一個集合 m,問你小於的 n的所有正數能整除 m的任意一個的數目。 析:簡單容斥,就是 1 個數的倍數 - 2個數的最小公倍數 + 3個數的最小公倍數 + ...(
HDU - 2141 : Can you find it?
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