獲取裝置唯一ID的幾種方式
部落格摘要:很簡單,就是獲取裝置的唯一ID,直接上正文。
先來看看幾種比較單一的方式:
IMEI
方式:TelephonyManager.getDeviceId():
問題
範圍:只能支援擁有通話功能的裝置,對於平板不可以。
永續性:返廠,資料擦除的時候不徹底,保留了原來的標識。
許可權:需要許可權:android.permission.READ_PHONE_STATE
bug: 有些廠家的實現有bug,返回一些不可用的資料
Mac地址
ACCESS_WIFI_STATE許可權
有些裝置沒有WiFi,或者藍芽,就不可以,如果WiFi沒有開啟,硬體也不會返回Mac地址,不建議使用
ANDROID_ID
2.2(Froyo,8)版本系統會不可信,來自主要生產廠商的主流手機,至少有一個普遍發現的bug,這些有問題的手機相同的ANDROID_ID: 9774d56d682e549c
但是如果返廠的手機,或者被root的手機,可能會變
Serial Number
從Android 2.3 (“Gingerbread”)開始可用,可以通過android.os.Build.SERIAL獲取,對於沒有通話功能的裝置,它會
返回一個唯一的device ID,
以下幾個是stackoverflow上評論較多的幾個,沒貼完,還有其他,綜合的,用到以上的部分方式:
有興趣的朋友可以再仔細看看
支援率比較高的(支援票數157):androidID --> 剔除2.2版本(API 8)中有問題的手機,使用UUID替代
import android.content.Context; import android.content.SharedPreferences; import android.provider.Settings.Secure; import android.telephony.TelephonyManager; import java.io.UnsupportedEncodingException; import java.util.UUID; public class DeviceUuidFactory { protected static final String PREFS_FILE = "device_id.xml"; protected static final String PREFS_DEVICE_ID = "device_id"; protected static volatile UUID uuid; public DeviceUuidFactory(Context context) { if (uuid == null) { synchronized (DeviceUuidFactory.class) { if (uuid == null) { final SharedPreferences prefs = context .getSharedPreferences(PREFS_FILE, 0); final String id = prefs.getString(PREFS_DEVICE_ID, null); if (id != null) { // Use the ids previously computed and stored in the // prefs file uuid = UUID.fromString(id); } else { final String androidId = Secure.getString( context.getContentResolver(), Secure.ANDROID_ID); // Use the Android ID unless it's broken, in which case // fallback on deviceId, // unless it's not available, then fallback on a random // number which we store to a prefs file try { if (!"9774d56d682e549c".equals(androidId)) { uuid = UUID.nameUUIDFromBytes(androidId .getBytes("utf8")); } else { final String deviceId = ((TelephonyManager) context.getSystemService( Context.TELEPHONY_SERVICE) .getDeviceId(); uuid = deviceId != null ? UUID .nameUUIDFromBytes(deviceId .getBytes("utf8")) : UUID .randomUUID(); } } catch (UnsupportedEncodingException e) { throw new RuntimeException(e); } // Write the value out to the prefs file prefs.edit() .putString(PREFS_DEVICE_ID, uuid.toString()) .commit(); } } } } } /** * Returns a unique UUID for the current android device. As with all UUIDs, * this unique ID is "very highly likely" to be unique across all Android * devices. Much more so than ANDROID_ID is. * * The UUID is generated by using ANDROID_ID as the base key if appropriate, * falling back on TelephonyManager.getDeviceID() if ANDROID_ID is known to * be incorrect, and finally falling back on a random UUID that's persisted * to SharedPreferences if getDeviceID() does not return a usable value. * * In some rare circumstances, this ID may change. In particular, if the * device is factory reset a new device ID may be generated. In addition, if * a user upgrades their phone from certain buggy implementations of Android * 2.2 to a newer, non-buggy version of Android, the device ID may change. * Or, if a user uninstalls your app on a device that has neither a proper * Android ID nor a Device ID, this ID may change on reinstallation. * * Note that if the code falls back on using TelephonyManager.getDeviceId(), * the resulting ID will NOT change after a factory reset. Something to be * aware of. * * Works around a bug in Android 2.2 for many devices when using ANDROID_ID * directly. * * @see http://code.google.com/p/android/issues/detail?id=10603 * * @return a UUID that may be used to uniquely identify your device for most * purposes. */ public UUID getDeviceUuid() { return uuid; } }
根據版本進行判斷的方式:Serial序列號-->UUID (支援數31)
通過Serial 即可,在覆蓋率上,你已經成功的獲得了98.4%的使用者,剩下的1.6%的使用者系統是在9 以下的。
通過AndroidID獲取,前面已經說過,在8上,有些商家的手機會有一些bug,返回相同的AndroidID,如果Serial和AndroidID都不行
/**
* Return pseudo unique ID
* @return ID
*/
public static String getUniquePsuedoID()
{
// If all else fails, if the user does have lower than API 9 (lower
// than Gingerbread), has reset their phone or 'Secure.ANDROID_ID'
// returns 'null', then simply the ID returned will be solely based
// off their Android device information. This is where the collisions
// can happen.
// Thanks http://www.pocketmagic.net/?p=1662!
// Try not to use DISPLAY, HOST or ID - these items could change.
// If there are collisions, there will be overlapping data
String m_szDevIDShort = "35" + (Build.BOARD.length() % 10) + (Build.BRAND.length() % 10) + (Build.CPU_ABI.length() % 10) + (Build.DEVICE.length() % 10) + (Build.MANUFACTURER.length() % 10) + (Build.MODEL.length() % 10) + (Build.PRODUCT.length() % 10);
// Thanks to @Roman SL!
// http://stackoverflow.com/a/4789483/950427
// Only devices with API >= 9 have android.os.Build.SERIAL
// http://developer.android.com/reference/android/os/Build.html#SERIAL
// If a user upgrades software or roots their phone, there will be a duplicate entry
String serial = null;
try
{
serial = android.os.Build.class.getField("SERIAL").get(null).toString();
// Go ahead and return the serial for api => 9
return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
}
catch (Exception e)
{
// String needs to be initialized
serial = "serial"; // some value
}
// Thanks @Joe!
// http://stackoverflow.com/a/2853253/950427
// Finally, combine the values we have found by using the UUID class to create a unique identifier
return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
}
不用READ_PHONE_STATE許可權直接獲取ROM資訊的方式:(支援率較低 16)
String m_szDevIDShort = "35" + //we make this look like a valid IMEI
Build.BOARD.length()%10+ Build.BRAND.length()%10 +
Build.CPU_ABI.length()%10 + Build.DEVICE.length()%10 +
Build.DISPLAY.length()%10 + Build.HOST.length()%10 +
Build.ID.length()%10 + Build.MANUFACTURER.length()%10 +
Build.MODEL.length()%10 + Build.PRODUCT.length()%10 +
Build.TAGS.length()%10 + Build.TYPE.length()%10 +
Build.USER.length()%10 ; //13 digits
最後貼上自己在專案中用的:
public static String getDeviceId(Context context) {
String deviceId = "";
if (deviceId != null && !"".equals(deviceId)) {
return deviceId;
}
if (deviceId == null || "".equals(deviceId)) {
try {
deviceId = getLocalMac(context).replace(":", "");
} catch (Exception e) {
e.printStackTrace();
}
}
if (deviceId == null || "".equals(deviceId)) {
try {
deviceId = getAndroidId(context);
} catch (Exception e) {
e.printStackTrace();
}
}
if (deviceId == null || "".equals(deviceId)) {
if (deviceId == null || "".equals(deviceId)) {
UUID uuid = UUID.randomUUID();
deviceId = uuid.toString().replace("-", "");
writeDeviceID(deviceId);
}
}
return deviceId;
}
// IMEI碼
private static String getIMIEStatus(Context context) {
TelephonyManager tm = (TelephonyManager) context
.getSystemService(Context.TELEPHONY_SERVICE);
String deviceId = tm.getDeviceId();
return deviceId;
}
// Mac地址
private static String getLocalMac(Context context) {
WifiManager wifi = (WifiManager) context
.getSystemService(Context.WIFI_SERVICE);
WifiInfo info = wifi.getConnectionInfo();
return info.getMacAddress();
}
// Android Id
private static String getAndroidId(Context context) {
String androidId = Settings.Secure.getString(
context.getContentResolver(), Settings.Secure.ANDROID_ID);
return androidId;
}
public static void saveDeviceID(String str) {
try {
FileOutputStream fos = new FileOutputStream(file);
Writer out = new OutputStreamWriter(fos, "UTF-8");
out.write(str);
out.close();
} catch (IOException e) {
e.printStackTrace();
}
}
public static String readDeviceID() {
StringBuffer buffer = new StringBuffer();
try {
FileInputStream fis = new FileInputStream(file);
InputStreamReader isr = new InputStreamReader(fis, "UTF-8");
Reader in = new BufferedReader(isr);
int i;
while ((i = in.read()) > -1) {
buffer.append((char) i);
}
in.close();
return buffer.toString();
} catch (IOException e) {
e.printStackTrace();
return null;
}
}
對於獲取裝置唯一ID並沒有絕對的方案,這一點在android的官方部落格中也提到了,不過以上幾種方案,應該可以滿足平時的需求,大家可以選擇其中自己認為比較好的,用於自己的專案中。不知道其他朋友在專案中是如何處理的,歡迎交流討論。