【lua】Lua正則表示式匹配郵箱
阿新 • • 發佈:2019-01-01
http://bbs.csdn.net/topics/390421795function isRightEmail(str) if string.len(str or "") < 6 then return false end local b,e = string.find(str or "", '@') local bstr = "" local estr = "" if b then bstr = string.sub(str, 1, b-1) estr = string.sub(str, e+1, -1) else return false end -- check the string before '@' local p1,p2 = string.find(bstr, "[%w_]+") if (p1 ~= 1) or (p2 ~= string.len(bstr)) then return false end -- check the string after '@' if string.find(estr, "^[%.]+") then return false end if string.find(estr, "%.[%.]+") then return false end if string.find(estr, "@") then return false end if string.find(estr, "[%.]+$") then return false end _,count = string.gsub(estr, "%.", "") if (count < 1 ) or (count > 3) then return false end return true end