Ricky’s RealDan’s Ricky
阿新 • • 發佈:2019-01-01
https://ac.nowcoder.com/acm/contest/322/H
題解:
當且僅當n==1,a【1】為偶數才能贏。。。。。。
/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int using namespace std; typedef long long ll; //typedef __int128 lll; const int N=100000+10; const int MOD=1e9+7; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; int t,n,m,k,q,ans; int a[N]; char str; int main() { #ifdef DEBUG freopen("input.in", "r", stdin); //freopen("output.out", "w", stdout); #endif scanf("%d",&t); while(t--){ scanf("%d",&n); ll sum=0; for(int i=1;i<=n;i++){ scanf("%d",&a[i]); if(a[i]%2==0){ sum++; } //sum+=a[i]; } if(sum==1){ cout << "Ricky is Winner" << endl; }else{ cout << "RealDan is Winner" << endl; } } //cout << "Hello world!" << endl; return 0; }