給定一個 Weather 表，編寫一個 SQL 查詢，來查詢與之前（昨天的）日期相比溫度更高的所有日期的 Id。

+---------+------------------+------------------+
| Id(INT) | RecordDate(DATE) | Temperature(INT) |
+---------+------------------+------------------+
|       1 |       2015-01-01 |               10 |
|       2 |       2015-01-02 |               25 |
|       3 |       2015-01-03 |               20 |
|       4 |       2015-01-04 |               30 |
+---------+------------------+------------------+
 

例如，根據上述給定的 Weather 表格，返回如下 Id:

+----+
| Id |
+----+
|  2 |
|  4 |
+----+

解決一：

select b.Id from Weather a ,Weather b 
where datediff(b.RecordDate,a.RecordDate)=1 and a.Temperature < b.Temperature

解決二：

select b.Id from Weather a ,Weather b 
where date_sub(b.RecordDate,interval 1 day) = a.RecordDate and
 
 a.Temperature < b.Temperature

解決三：

SELECT w1.Id FROM Weather w1, Weather w2
WHERE w1.Temperature > w2.Temperature AND TO_DAYS(w1.RecordDate)=TO_DAYS(w2.RecordDate) + 1;