給定一個 Weather 表，編寫一個 SQL 查詢，來查詢與之前（昨天的）日期相比溫度更高的所有日期的 Id。

+---------+------------------+------------------+
| Id(INT) | RecordDate(DATE) | Temperature(INT) |
+---------+------------------+------------------+
|       1 |       2015-01-01 |               10 |
|       2 |       2015-01-02 |               25 |
|       3 |       2015-01-03 |               20 |
|       4 |       2015-01-04 |               30 |
+---------+------------------+------------------+

例如，根據上述給定的 Weather 表格，返回如下 Id:

+----+
| Id |
+----+
|  2 |
|  4 |
+----+

解析：

1、使用MySQL的函式Datadiff來計算兩個日期的差值，限制條件為溫度高且日期差1。

select w1.Id from weather w1
inner join weather w2 
on w1.Temperature > w2.Temperature and DATEDIFF(w1.RecordDate, w2.RecordDate) = 1;

2、使用MySQL的TO_DAYS函式，用來將日期換算成天數。

SELECT w1.Id FROM Weather w1, Weather w2
WHERE w1.Temperature > w2.Temperature AND TO_DAYS(w1.RecordDate) = TO_DAYS(w2.RecordDate) + 1;

3、使用Subdate函式實現日期減1。

SELECT w1.Id FROM Weather w1, Weather w2
WHERE w1.Temperature > w2.Temperature AND SUBDATE(w1.RecordDate, 1) = w2.RecordDate;