LeetCode29. Divide Two Integers(C++)
阿新 • • 發佈:2019-01-14
Given two integers dividend
and divisor
, divide two integers without using multiplication, division and mod operator.
Return the quotient after dividing dividend
by divisor
.
The integer division should truncate toward zero.
Example 1:
Input: dividend = 10, divisor = 3 Output:3
Example 2:
Input: dividend = 7, divisor = -3 Output: -2
Note:
- Both dividend and divisor will be 32-bit signed integers.
- The divisor will never be 0.
- Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 231 − 1 when the division result overflows.
特殊情況,當被除數為-2^31,除數為-1,可能會溢位
class Solution {
public:
int divide(int dividend, int divisor) {
if(dividend==-2147483648&&divisor==-1)
return 2147483647;
return dividend/divisor;
}
};